In the given table,identify the incorrect opt | vedclass

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(D) Periodic acid $(HIO_4)$ cleaves the $C-C$ bond of vicinal diols ($1,2$-diols).- In option $(a)$,$HO-CH_2-CH(OH)-CH_2-OH$ has two vicinal $C-C$ bon

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$HO-CH_2-CH(OH)-CH_2-OCH_3$$\boxed{1}$$\boxed{1}$$\boxed{1}$

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(D) Periodic acid $(HIO_4)$ cleaves the $C-C$ bond of vicinal diols ($1,2$-diols).- In option $(a)$,$HO-CH_2-CH(OH)-CH_2-OH$ has two vicinal $C-C$ bonds. Cleavage consumes $2$ moles of $HIO_4$ and produces $2$ moles of $HCHO$ and $1$ mole of $HCO_2H$.- In option $(b)$,$R-CH(OH)-CH(OH)-CH(OH)-CH_2-OH$ has three vicinal $C-C$ bonds. Cleavage consumes $3$ moles of $HIO_4$ and produces $1$ mole of $HCHO$ and $2$ moles of $HCO_2H$.- In option $(c)$,$HO-CH_2-CH(OCH_3)-CH_2-OH$ has no vicinal diols (the middle group is an ether),so no reaction occurs.- In option $(d)$,$HO-CH_2-CH(OH)-CH_2-OCH_3$ has only one vicinal $C-C$ bond (between $C_1$ and $C_2$). Cleavage consumes $1$ mole of $HIO_4$ and produces $1$ mole of $HCHO$ and $0$ moles of $HCO_2H$. Therefore,the table values for option $(d)$ are incorrect.

In the given table,identify the incorrect option. The digit in the box indicates the moles of that substance.
Reactant $HIO_4$ consumed $HCO_2H$ formed $HCHO$ formed

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In the given table,identify the incorrect option. The digit in the box indicates the moles of that substance.Reactant$HIO_4$ consumed$HCO_2H$ formed$HCHO$ formed